如何将随机种子分配给 dplyr sample_n function？

Question

This is the "sample_n" from dplyr in R.
https://dplyr.tidyverse.org/reference/sample.html

For reproducibility, I should place a seed so that someone else can get my exact results.

Is there a built-in way to set the seed for "sample_n"? Is this something that I do in the environment and "sample_n" responds to it?

These are not built-into the "sample_n" function.

• There is the environment "set.seed" function [1]
• There is a library 'withr' that creates a seed-containing wrapper for code [2]

.

Answer 1

The dplyr::sample_n documentation tells that:

This is a wrapper around sample.int() to make it easy to select random rows from a table. It currently only works for local tbls.

so behind sample_n , sample.int is called, which means that the standard Random Number Generator is used, and that you can use set.seed for reproducibility.

Answer 2

Does this example help? In it, I am using set.seed and the mtcars dataset.

set.seed(1)
x <- mtcars
sample_n(x, 10)

sample_n(x, 10) #without set.seed()

set.seed(1)
x <- mtcars
sample_n(x, 10)