[英]How to compare (x,y) points for sorting, where x is always first
I'm using Java Comparator to compare location objects with points (x,y).我正在使用 Java Comparator 将位置对象与点 (x,y) 进行比较。
I need to be able to compare two points to retrieve a positive or negative integer that will allow me to sort (x,y) points, where x-values are sorted first, then y-values secondly.我需要能够比较两个点以检索一个正整数或负整数,这将允许我对 (x,y) 点进行排序,其中首先对 x 值进行排序,然后对 y 值进行排序。 (If that makes sense...) For example, this:
(如果这是有道理的......)例如,这个:
(3,4) (2,5) (1,1) (1,3) (3,3)
Becomes this:变成这样:
(1,1) (1,3) (2,5) (3,3) (3,4)
One way I've thought to do it is essentially by giving the x-value large precedence by multiplying it by a large number like 1000. Like so: Comparing (3,3) and (1,1):我想这样做的一种方法基本上是通过将 x 值乘以像 1000 这样的大数来赋予 x 值较大的优先级。像这样:比较 (3,3) 和 (1,1):
int x_multiplier = 1000;
int value1 = (p1.x * x_multiplier ) + p1.y; // = 3 * 1000 + 3 = 3003
int value2 = (p2.x * x_multiplier ) + p2.y; // = 1 * 1000 + 1 = 1001
return value1-value2; // = 2002. Value1 is greater, thus p1 be later in list.
This works, but the issue with this is if the Y-value should ever be equal to or greater than the x_multiplier, then this breaks down (because that y-value is now equal to 1 x-value... again, if that makes sense.)这是有效的,但问题是如果 Y 值应该等于或大于 x_multiplier,那么它就会崩溃(因为 y 值现在等于 1 x 值......再次,如果说得通。)
// Comparing p1 = (2,0) & p2 = (1,18)
int x_multiplier = 10;
int value1 = (p1.x * x_multiplier ) + p1.y; // = 2 * 10 + 0 = 20
int value2 = (p2.x * x_multiplier ) + p2.y; // = 1 * 10 + 18 = 28
return value1-value2; // = -8, value2 is greater, and thus p2 will be later in the list. However, we know by looking at the points that p2 should come first.
I don't really even know how to search for this, so if there are answers out there I couldn't find them.我什至不知道如何搜索这个,所以如果有答案,我找不到它们。
import java.util.*;
class Tuple {
public int x, y;
Tuple(int x, int y) {
this.x = x;
this.y = y;
}
@Override
public String toString() {
return "(" + x + ", " + y + ") ";
}
}
public class coord {
public static void main(String[] args) {
LinkedList<Tuple> list = new LinkedList<Tuple>();
list.add(new Tuple(3,4));
list.add(new Tuple(2,5));
list.add(new Tuple(1,1));
list.add(new Tuple(1,3));
list.add(new Tuple(3,3));
for (Tuple t: list) {
System.out.print(t);
}
Collections.sort(list, (Tuple t1, Tuple t2) -> {
int result = Integer.compare(t1.x, t2.x);
if (result == 0 ) result = Integer.compare(t1.y, t2.y);
return result;
});
System.out.println("Sorted List: ");
for (Tuple t: list) {
System.out.print(t);
}
}
}
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