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Pandas 根据其他列值从另一个更新一个 df

[英]Pandas update one df from another based on other columns value

I have two dataframes:我有两个数据框:

df1: df1:

   A  B  C
0  1  3  5
1  2  4  6

df2: df2:

   A  B   C
0  1  3  50
1  3  5  -1
2  2  4  60

And now I want to update df1 from df2 based on the same values from A and B , to get something like this:现在我想根据AB的相同值从 df2 更新 df1 ,以获得如下内容:

   A  B  C
0  1  3  50
1  2  4  60

What did I try:我尝试了什么:

  • .update() results in A[1] == 3 nad B[1] == 5 , it just goes in order, doesn't match the key (because I cannot specify it there) .update()结果A[1] == 3 nad B[1] == 5 ,它只是按顺序进行,与密钥不匹配(因为我不能在那里指定它)
  • .merge() with left join and on=["A", "B"] - best I got so far, it does preserve the result df to just 2 rows with A=1,2 and B=3,4 , but it adds columns C_x and C_y , the latter with the values I want, but I want them to be in C .merge() with left join and on=["A", "B"] - 到目前为止我得到的最好的结果,它确实将结果 df 保留为A=1,2B=3,4的 2 行,但是它添加了列C_xC_y ,后者具有我想要的值,但我希望它们位于C

Is there a clean way to do this, or should I go for .merge() and just remove the column with _x suffix + rename the C_y to C ?有没有一种干净的方法可以做到这一点,或者我应该为.merge()并删除带有_x后缀的列 + 将C_y重命名为C

Drop C in df1 then merge将 C 放入 df1 然后合并

df1.drop('C', axis=1).merge(df2, on=['A', 'B'], how='left')

   A  B   C
0  1  3  50
1  2  4  60

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