当键的值是列表列表时，如何将字典转换为 dataframe？

Question

I have dataframe that looks like this..

{'abc2035': [['abc3007', 2],['abc2006', 2],['abc2003', 1],['abc3000', 3]],
 'abc2001': [['abc3002', 1],['abc2096', 2],['abc2003', 2],['abc3009', 3],['abc2015',3]],
 'abc2052': [['abc1003', 2],['abc2090', 2]],
.
.
.}

I want to convert it to a dataframe like this..

userID    with_common   no_of_common
abc2035    abc3007       2
abc2035    abc2006       2
abc2035    abc2003       1
abc2035    abc3000       3
abc2001    abc3002       1
abc2001    abc2096       2
abc2001    abc2003       2
abc2001    abc3009       3
abc2001    abc2015       3
.
.
.

Any help on this?

Answer 1

Use:

cols = ['userID',' with_common','no_of_common']
df = pd.DataFrame([(k, *x) for k, v in d.items() for x in v], columns=cols)
print (df)
     userID  with_common  no_of_common
0   abc2035      abc3007             2
1   abc2035      abc2006             2
2   abc2035      abc2003             1
3   abc2035      abc3000             3
4   abc2001      abc3002             1
5   abc2001      abc2096             2
6   abc2001      abc2003             2
7   abc2001      abc3009             3
8   abc2001      abc2015             3
9   abc2052      abc1003             2
10  abc2052      abc2090             2