python 中的立方体 - 散点颜色的设置

Question

How to prevent the scatters from changing the colour in dependence on the angle of view, please?

import numpy as np
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
from itertools import product, combinations

fig = plt.figure(figsize=[10,6])
ax = fig.gca(projection='3d')
ax.azim = -112   # y rotation (default=270)
ax.elev = 31     # x rotation (default=0)

ax.get_proj = lambda: np.dot(Axes3D.get_proj(ax), np.diag([0.2, 1, 1, 1]))

r = [-1, 1]
for s, e in combinations(np.array(list(product(r, r, r))), 2):
    if np.sum(np.abs(s-e)) == r[1]-r[0]:
        ax.plot3D(*zip(s, e), color='black', lw=1.5)

x_w = [0.5, 0.3]
y_w = [0, 0.6]
z_w = [0, -0.6]
ax.scatter(x_w, y_w, z_w, marker = 'o', s=500, facecolors=(0, 0, 0, 0), edgecolors = 'black')

ax._axis3don = False
plt.show()

Answer 1

One solution to avoid this is to plot each point individually via

for i in range(len(x_w)):
    ax.scatter(x_w[i], y_w[i], z_w[i], marker = 'o', s=500, facecolors=(0, 0, 0, 0), edgecolors = 'black' )

If this is not an option for you, you may want to have a look into this or this thread. The argument depthshade = False may be the solution you are looking for. Unfortunately, I was unable to get the code to run with depthshade turned off. It is not working for instances with more than one point in my matplotlib installation, but this link might point you to a solution.