如何使用 Pandas 中的另一个 DataFrame 填充 DataFrame 中的缺失值

Question

my df looks like this:

sprint   sprint_created
------   -----------
S100     2020-01-01    
S101     2020-01-10
NULL     2020-01-20
NULL     2020-01-31
S101     2020-01-10
...

in the above df , you can see that some of the sprint values are NULL

I have another df2 that has sprint date ranges:

sprint   sprint_start   sprint_end
------   -----------    ----------
S100     2020-01-01     2020-01-09    
S101     2020-01-10     2020-01-19  
S102     2020-01-20     2020-01-29  
S103     2020-01-30     2020-02-09  
S104     2020-02-10     2020-02-19  
...

How can I map these data and fill in the NULL values in the df by comparing the data in the df2 ?

Please note that the shape of df and df2 are different.

Answer 1

I assummed duplicated sprint in df(first dataframe can be dropped). Please advice otherwise if not so. I use merge asof with one day tolerance based on my comparison of the two dfs you provided. Advice otherwise if so

df.assign(sprint=pd.merge_asof( df.drop_duplicates(keep='first'), df1, left_on="sprint_created", right_on="sprint_start", tolerance=pd.Timedelta("1D"))['sprint_y']).dropna()

  sprint sprint_created
0   S100     2020-01-01
1   S101     2020-01-10
2   S102     2020-01-20
3   S103     2020-01-31

If your frame has legit multiple sprints as explained above in comments. Please try;

g=df.assign(sprint=pd.merge_asof( df.drop_duplicates(keep='first'), df1, left_on="sprint_created", right_on="sprint_start", tolerance=pd.Timedelta("1D"))['sprint_y'])
g.loc[g.sprint.isna(), 'sprint']=g.groupby('sprint_created').sprint.ffill()
print(g)



sprint sprint_created
0   S100     2020-01-01
1   S101     2020-01-10
2   S102     2020-01-20
3   S103     2020-01-31
4   S101     2020-01-10

Answer 2

One way would be to melt and resample your df2 and create a dictionary to map back to df1 :

#make sure columns are in datetime format
df1['sprint_created'] = pd.to_datetime(df1['sprint_created'])
df2['sprint_start'] = pd.to_datetime(df2['sprint_start'])
df2['sprint_end'] = pd.to_datetime(df2['sprint_end'])

#melt dataframe of the two date columns and resample by group
new = (df2.melt(id_vars='sprint').drop('variable', axis=1).set_index('value')
          .groupby('sprint', group_keys=False).resample('D').ffill().reset_index())

#create dictionary of date and the sprint and map back to df1
dct = dict(zip(new['value'], new['sprint']))
df1['sprint'] = df1['sprint_created'].map(dct)
#or df1['sprint'] = df1['sprint'].fillna(df1['sprint_created'].map(dct))
df1
Out[1]: 
  sprint sprint_created
0   S100     2020-01-01
1   S101     2020-01-10
2   S102     2020-01-20
3   S103     2020-01-31
4   S101     2020-01-10