如何通过列值的条件删除 DataFrame 中的行

Question

I created code to drop some rows according to certain condition:

df3 = df_clean[(df_clean['group'] == 'treatment') & (df_clean['landing_page'] != 'new_page')].index
df2 = df_clean.drop(df3 , inplace=True)
df2.head()

but I got this error: AttributeError: 'NoneType' object has no attribute 'head'

Answer 1

You can do something like this. I dont have your dataset so using my own.

import pandas as pd
df = pd.DataFrame({'A':[100,200,300,400,500,600,700,800],
                   'B':['apple','banana','apple','banana',
                        'apple','banana','apple','banana']})

print (df)
df1 = df[(df['A'] >400) & (df['B'] == 'apple')]
print (df1)

If I want to get all the rows with 'apple' and values > 400, then, df1 will give me the result.

     A       B
0  100   apple
1  200  banana
2  300   apple
3  400  banana
4  500   apple
5  600  banana
6  700   apple
7  800  banana
     A      B
4  500  apple
6  700  apple

Answer 2

Assign df_clean to df2 without the inplace

 df2 = df_clean.drop(df3)

Or leave the inplace without assigning, here df_clean will be your output

 df_clean.drop(df3 , inplace=True)