[英]Questions regarding String.charAt(); in Java
I am recently working on an algorithm question from Leetcode.我最近正在研究 Leetcode 的一个算法问题。 But I am really confused with this line of code shown below.
但是我真的对下面显示的这行代码感到困惑。 And I do not actually understand what is the meaning of
而且我实际上不明白是什么意思
(char)(str.charAt(loop) + 1))
Can anyone explain this to me?谁能给我解释一下? Furthermore,
sb
means此外,
sb
表示
StringBuilder sb = new StringBuilder();
In case you guys do not know what is sb
.如果你们不知道什么是
sb
。
Here is the full code:这是完整的代码:
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
while (scanner.hasNext()) {
String str = scanner.nextLine();
StringBuilder sb = new StringBuilder();
for (int loop = 0; loop < str.length(); loop++) {
if (str.charAt(loop) == 'Z') {
sb.append("a");
continue;
}
if (str.charAt(loop) >= '0' && str.charAt(loop) <= '9') {
sb.append(String.valueOf(str.charAt(loop)));
continue;
}
if (str.charAt(loop) >= 'A' && str.charAt(loop) < 'Z') {
sb.append(String.valueOf((char)(str.charAt(loop) + 1)).toLowerCase());
continue;
}
else {
switch (str.charAt(loop)) {
case('1'):
sb.append("1");
break;
case('a'):
case('b'):
case('c'):
sb.append("2");
break;
case('d'):
case('e'):
case('f'):
sb.append("3");
break;
case('g'):
case('h'):
case('i'):
sb.append("4");
break;
case('j'):
case('k'):
case('l'):
sb.append("5");
break;
case('m'):
case('n'):
case('o'):
sb.append("6");
break;
case('p'):
case('q'):
case('r'):
case('s'):
sb.append("7");
break;
case('t'):
case('u'):
case('v'):
sb.append("8");
break;
case('w'):
case('x'):
case('y'):
case('z'):
sb.append("9");
break;
}
}
}
System.out.println(sb.toString());
}
}
}
You have to dissect the expression into its parts:您必须将表达式分解为各个部分:
String.valueOf(
(char)
(str.charAt(loop) + 1)
).toLowerCase());
So, on the "innermost" call (str.charAt(loop) + 1)
a single char value is retrieved from str
.因此,在“最内层”调用
(str.charAt(loop) + 1)
中,从str
检索到单个 char 值。 Then 1 is added to that (remember that char is also a "numerical" type that allows for numerical operations).然后将 1 添加到其中(请记住, char 也是允许数字运算的“数字”类型)。 Then the result of that is turned into a String again, when is then forced to be a lower case string.
然后它的结果再次变成一个字符串,然后强制成为一个小写字符串。
For the why to do that we would need more context.对于为什么要这样做,我们需要更多的上下文。
This line of code is simply encoding a string by caesar ciper of +1, in other word, if you put this line in a loop it will create a string of every char is the upper char in the alphabet, for example banana will be cboboc For more about caesar ciper look in https://en.m.wikipedia.org/wiki/Caesar_cipher这行代码只是用 +1 的 caesar ciper 对字符串进行编码,换句话说,如果你把这行放在一个循环中,它将创建一个字符串,每个字符都是字母表中的大字符,例如香蕉将是 cboboc有关凯撒 ciper 的更多信息,请查看https://en.m.wikipedia.org/wiki/Caesar_cipher
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