Python 3.5+ 的 OrderedDict move_to_end 替代品

Question

I have a dict with n parameters:

print(table)
{
    "Parameters":{
        "erVersion":"1.0",
        "A":"a",
        "rVersion":"1.0",
        "B":"b",
        "C":"c",
        "Ur":"legislator",
        "RecordSize":"13",
        "classification":"json",
        "compressionType":"none"
    }
}

I wanted to place the parameters A, B and C to the top of parameters. I tried doing this with the following code:

table['Parameters'].move_to_end("C", last=False)
table['Parameters'].move_to_end("B", last=False)
table['Parameters'].move_to_end("A", last=False)

This however doesn't work as of Python 3.5+ (refference: https://stackoverflow.com/a/16664932/7615751 )

Is there an alternative to this with newer versions of Python? If a different approach is better I'd also appreciate the suggestion to use it.

I don't want to solve this by defining a fixed parameter order because I have a lot of tables like this with a different number of parameters (they always have the A, B, C parameter though).

Answer 1

Let's assume

data = {
    "Parameters":{
        "erVersion":"1.0",
        "A":"a",
        "rVersion":"1.0",
        "B":"b",
        "C":"c",
        "Ur":"legislator",
        "RecordSize":"13",
        "classification":"json",
        "compressionType":"none"
    }
}

You seem to be doing table = OrderedDict(data) , which will create said object for only the key 'Parameters'. The value of that, ie, the inner dictionary, will remain a normal dict , which doesn't support move_to_end() . You can address that with

table['Parameters'] = OrderedDict(table['Parameters'])