从特定列表中的关键字之前从句子中删除单词

Question

I have a list of keywords keywords = [",", "or", "and"] and a sentence s = built on the kernel, is written largely in

I want to remove all the words from the above sentence before any keyword from the above list, in this case ",". So the Output will be is written largely in.

Answer 1

import re

keywords = [",", "or", "and"]
s = "built on the kernel, is written largely in"
split_sentence = re.split(',|or|and',s)[1:]
result = "".join(split_sentence)
print(result)

output:

is written largely in

Answer 2

You can use re.split() with pattern as | joined string of your keywords . It will return you list of strings separated by your keywords. Since you need the last sub-string from the list , you can access it using -1 as index.

For example:

>>> import re
>>> keywords = [",", "or", "and"]
>>> my_str = "Hello, and, or, Stack Overflow"

>>> re.split('|'.join(keywords), my_str)[-1]
' Stack Overflow'

Additionally, if you want to remove additional white spaces from the resultant string, then you can further usestr.strip() on the above string as:

>>> re.split('|'.join(keywords), my_str)[-1].strip()
'Stack Overflow'