[英]How do I create a loop repeating the following but each time deducting 0.1 from a?
How do I create a loop repeating the following but each time deducting 0.1 more from a=10 ?如何创建一个循环重复以下内容,但每次从a=10中减去 0.1 ? It should repeat a 100 times and then stop.它应该重复 100 次然后停止。 Thanks!谢谢!
for i in x:
yt = (a - 0.1)* i
MSE = np.square(np.subtract(y,yt)).mean()
You could use a while loop instead, like the following:您可以改用 while 循环,如下所示:
a = 10
while a > 0:
yt = (a-0.1)
MSE = np.square(np.subtract(y,yt)).mean()
a -= 0.1
That way, if a == 0 the loop stops and yt won't become 0. If that is what you are asking for.这样,如果 a == 0 循环停止并且 yt 不会变为 0。如果那是您所要求的。 Due to accurancy problems, often a repeated -0.1 will result in rounding errors and could create unwanted results.由于精度问题,通常重复的 -0.1 会导致舍入错误,并可能产生不需要的结果。 Thus I recommand using something like this:因此我建议使用这样的东西:
a = 100
while a > 0:
yt = (a/10-0.1)
MSE = np.square(np.subtract(y,yt)).mean()
a -= 1
Alternatively after the newest comment: Using temporary values which get compared iteratively every loop index:或者在最新评论之后:使用每个循环索引迭代比较的临时值:
import numpy as np
a = 10
y = 5.423 #example value
tmp_MSE = np.infty #the first calculated MSE is always smaller then infty
tmp_a = a #if no modified a results in a better MSE, a itself is closest
for i in range(100):
yt = a-0.1*(i+1)
MSE = np.square(np.subtract(y,yt)).mean()
if MSE < tmp_MSE: #new MSE comparison
tmp_MSE = MSE #tmp files are updated
tmp_a = yt
print("nearest value of a and MSE:",tmp_a,tmp_MSE)
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