如何从 DataFrame 中删除多个索引？

Question

fm2_age = fm1_age.drop(fm1_age.index[(fm1_age > df['age'].median() + 35)])

fm2_age = fm2_age.drop(fm2_age.index[(fm2_age < df['age'].median() - 15)])

How can I simplify these lines onto a single one, I tried using this code but it doesn't seem to work

fm2_age = fm1_age.drop(fm1_age.index[(fm1_age > df['age'].median() + 35) &(fm2_age < df['age'].median() - 15)])

Answer 1

Instead of dropping, you can filter for what you want to keep:

keep = df['age'].median() + [-15, 35]
fm1_age[fm11_age.between(*keep)]