如何从 numpy 数组中提取居中的 window？

Question

Suppose I have the following numpy array:

>>> a = np.arange(0,21,1)
>>> a
array([ 0,  1,  2,  3,  4,  5,  6,  7,  8,  9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20])

Now suppose that I want to pick a window of length N , where 2 < N <= a.shape[0] , such that the window is "centered" around one of the elements of the array a . For example, if I want to center a window of length N = 5 around the element 10 in array a , then this window would be:

>>> idx = 10 # index of the array element 10
>>> N = 5 # window size
>>> a[idx - N//2:idx + N//2 + 1]
array([ 8,  9, 10, 11, 12])

This method generalizes well for windows that are not near the edges of the array, but I can't make it work otherwise. For example, if I want to extract a window of length N = 7 around the element 2 in a , then what I get is:

>>> idx = 2
>>> N = 7
>>> a[idx - N//2:idx + N//2 + 1]
array([], dtype=int32)

However what I want is:

>>> a[0:7]
array([0, 1, 2, 3, 4, 5, 6])

How can I generalize this method for windows near the edges of a ?

Answer 1

Try with:

idx = 2
start = min(idx - N//2, 0)
a[start:start + N]

Note that this is not centered at idx=2 .

Answer 2

Based on Quang Hoang's answer , here is what worked:

import numpy as np

a = np.arange(0,21,1)
idx = 5 # desired element index
N = 7 # window length

if N % 2: # if window length is odd
    step = N // 2
else: # if window length is even
    step = int(N/2 - 1)

# make sure starting index is between 0 and a.shape[0] - N
start = min(max(idx-step,0),a.shape[0] - N)
window = a[start:start + N]