从 Python 中的键列表和值的多列表创建字典

Question

I have a list of key:

list_date = ["MON", "TUE", "WED", "THU","FRI"]

I have many lists of values that created by codes below:

list_value = list()
for i in list(range(5, 70, 14)):
    list_value.append(list(range(i, i+10, 3)))

Rules created that:

• first number is 5, a list contains 4 items has value equal x = x + 3, and so on [5, 8, 11,1 4]

• the first number of the second list equal: x = 5 + 14, and value inside still as above x = x +3

  [[5, 8, 11, 14], [19, 22, 25, 28], [33, 36, 39, 42], [47, 50, 53, 56], [61, 64, 67, 70]]

I expect to obtain a dict like this:

collections = {"MON":[5, 8, 11, 14], "TUE" :[19, 22, 25, 28], "WED":[33, 36, 39, 42], "THU":[47, 50, 53, 56], "FRI":[61, 64, 67, 70]}

Then, I used:

zip_iterator = zip(list_date, list_value)
collections = dict(zip_iterator)

To get my expected result.

I tried another way like using lambda function

for i in list(range(5, 70, 14)):
    list_value.append(list(range(i,i+10,3)))
    couple_start_end[lambda x: x in list_date] = list(range(i, i + 10, 3))

And the output is:

{<function <lambda> at 0x000001BF7F0711F0>: [5, 8, 11, 14], <function <lambda> at 0x000001BF7F071310>: [19, 22, 25, 28], <function <lambda> at 0x000001BF7F071280>: [33, 36, 39, 42], <function <lambda> at 0x000001BF7F0710D0>: [47, 50, 53, 56], <function <lambda> at 0x000001BF7F0890D0>: [61, 64, 67, 70]}

I want to ask there is any better solution to create lists of values with the rules above? and create the dictionary collections without using the zip method?

Thank you so much for your attention and participation.

Answer 1

Sure, you can use enumerate but I wouldn't say it is in anyway better or worse than the zip based solution:

collections = {}
for idx, key in enumerate(list_keys):
    collections[key] = list_value[idx]
print(collections)

Output:

{'MON': [5, 8, 11, 14], 'TUE': [19, 22, 25, 28], 'WED': [33, 36, 39, 42], 'THU': [47, 50, 53, 56], 'FRI': [61, 64, 67, 70]}

Further, you don't need to create the value list separately, you can create the dictionary as you go along:

list_keys = ["MON", "TUE", "WED", "THU","FRI"]
collections = {}
for idx, start in enumerate(range(5, 70, 14)):
    collections[list_keys[idx]] = [i for i in range(start, start+10, 3)]
print(collections)