将元组列表中的所有元素与列表中的元素相乘

Question

I know it might sound easy but that problem is making me struggle.我知道这听起来很容易，但这个问题让我很挣扎。

I have a list of tuple as我有一个元组列表

[(0,1),(3,4)]

And I want to multiply all its values for all the values in a list like我想将其所有值乘以列表中的所有值，例如

[ 1, 2, 3]

So That in this case I will get a new list (nested) of tuples:所以在这种情况下，我将得到一个新的元组列表（嵌套）：

[[(0,1),(0,2),(0,3)],[(3,4),(6,8),(9,12)]]

How can I obtain this result?我怎样才能得到这个结果？

Answer 1

Using a list comprehension:使用列表推导：

tuples = [(0,1),(3,4)]
multipliers = [1, 2, 3]

results = [[(t[0]*m, t[1]*m) for m in multipliers] for t in tuples]

Answer 2

nested loops.嵌套循环。

result = []
for t in tuples:
    for m in multipliers:
        result.append( (t[0]*m, t[1]*m) )

print(result)

gives:给出：

[(0, 1), (0, 2), (0, 3), (3, 4), (6, 8), (9, 12)]

This is a list of tuples (the inner list).这是一个元组列表（内部列表）。