[英]multiply list by list of ndarrays
I want to multiply a list of numbers, by a ndarray, that is, each number in the list multiply by the first ndarray.我想将一个数字列表乘以一个ndarray,即列表中的每个数字乘以第一个ndarray。
This is the list:这是列表:
rad_glob = list(df_radiation_global['Radiacion Global'])
rad_glob
[840.6019233865843,
838.5216723344233,
848.0960914721192,
868.2549621516736,
856.395770948553,
834.7011163700374,
845.9590749318633,
879.446257064898,
650.7904290945771,
814.4754071050489,
736.1105621236436,
736.0329394056781,
873.7764268803811,
870.1957716272296,
904.985074880194,
858.1357154671834,
830.0583941643629,
878.693702287297,
848.669553553067,
863.545204861961,
825.3890093196567,
842.5188280674437,
865.3524589935482,
833.5260196891436,
276.4022647360663,
915.9376255942822,
864.3266555276591,
770.448229104661,
857.8907668737729,
837.7897681015845,
838.6796919844484,
416.3444326406533,
568.653862415028,
884.4158558809625,
825.3940207623805,
798.0613412638792,
863.0410218716003]
This is the list/df of ndarray这是 ndarray 的列表/df
alb_lo = df_radiation_global['1 - Albedo']
alb_lo
0 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
1 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
2 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
3 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
4 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
5 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
6 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
7 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
8 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
9 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
10 [[nan, nan, nan, nan, nan, nan, 0.781219920000...
11 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
12 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
13 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
14 [[nan, 0.79422526, 0.7942568400000001, 0.79905...
15 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
16 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
17 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
18 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
19 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
20 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
21 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
22 [[nan, nan, nan, nan, nan, nan, 0.80179372, 0....
23 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
24 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
25 [[nan, nan, 0.85725789, 0.85735359, 0.86033684...
26 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
27 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
28 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
29 [[nan, nan, nan, nan, nan, 0.84266864, nan, na...
30 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
31 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
32 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
33 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
34 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
35 [[nan, nan, nan, nan, nan, nan, nan, 0.8528845...
36 [[nan, nan, nan, nan, nan, nan, nan, nan, nan,...
Name: 1 - Albedo, dtype: object
I want to multiply the first item in the list by the first ndarray.我想将列表中的第一项乘以第一个 ndarray。 The nan values remain nan and just multiply the float numbers. nan 值仍然是 nan 并且只是乘以浮点数。 I have tried with map, lambda function, iterations with for but I have not succeeded.我已经尝试过使用 map、lambda function 进行迭代,但我没有成功。 The error that I get frequently is:我经常遇到的错误是:
TypeError: can't multiply sequence by non-int of type 'str'. It can create a separate column with the new data, or simply create a list.
all what you need to do is creaating new class from list class that can handle nan elements so you do not get exception try: var=[2,2,3]*"None" except Exception as yourexception: print("this is your error.let me show you how to fix it ",yourexception) class list_handle_none(list):您需要做的就是从列表 class 中创建新的 class 可以处理 nan 元素,因此您不会遇到异常尝试: var=[2,2,3]*"None" except Exception as yourexception: print("this is your错误。让我告诉你如何修复它“,你的异常)class list_handle_none(list):
def __mul__(self, other):
if type(other)==type(3):
return list(self)*other
elif type(other)==type("nan"):
# raise TypeError("can't multiply sequence by non-int of type 'list'")
def handling_none(a):
if "nan" in[a,other]:
return "nan"
else:
return a*b
return list(map(handling_none,list(self)))
print(list_handle_none([1,2,3]))
print(list_handle_none([1,2,3])*"nan")
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.