我如何在 Python 从一开始就执行 def 下的脚本列表

Question

Sorry I am considered quite new to Python but I still hope I can get help from here.

So I made a rock paper scissor game, and the script needs to be executed again after one round is over. The script looks something like this:

def introStuff():
  window.geometry("300x300")
  window.title("Rock Paper Scissor")
  welcomeMessage=Label(window, text="Welcome to Rock Paper Scissor!", font=("Arial Bold", 15))
  welcomeMessage.grid(column=0, row=0)
  welcomeButton=Button(window, text="Start game", bg="green", fg="white", command=startGame)
  welcomeButton.grid(column=0, row=3)

So I placed the script under def introStuff() . I know how to restart the script by using command=introStuff in a button that user clicks after one round, but the issue is that the script introStuff needs to execute upon launch to start a game of rock paper scissors, but I am unaware of any code that can accomplish that. Any suggestions?

Answer 1

Where to call the function?

It depends how you launch your game. If there is some launch lifecycle hooks in whatever game framework you are using, then typically just calling your introStuff function in that framework launch sequence will work.

In other words, the framework you are using probably does some stuff when it is launched, and probably has provisioned ways to allow you to hook into this launch stage to run your own code. It is simply a matter of determining how the framework exposes this functionality, which depends on the framework.

How to call the function?

You can call the function, which will execute the code indented below it, by using the parentheses operators. Since the function definition does not specify any parameters, to call the function we need not supply any arguments, so the parentheses are empty:

introStuff()