Django TypeError: get() 得到了一个意外的关键字参数“quiz_name”

Question

I am trying to access a url from flutter webview , however, I am getting the following error. When I try to access this directly, I dont see any error.

File "/home/quiz/views.py", line 629, in dispatch
    return super(QuizTakeAutoAuth, self).dispatch(request, *args, **kwargs)
TypeError: get() got an unexpected keyword argument 'quiz_name'

views.py

class QuizTakeAutoAuth(APIView):

    authentication_classes = (TokenAuthentication,)
    permission_classes = (IsAuthenticated,)

   
    def get(self, request, format=None):
        content = {
            'foo': 'bar'
        }
        
        return Response(content)

   
    def dispatch(self, request, *args, **kwargs):
        self.quiz = get_object_or_404(Quiz, url=self.kwargs['quiz_name'])

        if self.quiz.draft and not request.user.has_perm('quiz.change_quiz'):
            raise PermissionDenied

        if self.sitting is False:
            print("sitting false")
            if self.logged_in_user:
                return render(request, self.single_complete_template_name)
            else:                    
                redirecturl = "/login/?next=/quiz/"+self.kwargs['quiz_name']+"/startquiz/"
                return redirect(redirecturl)   

        return super(QuizTakeAutoAuth, self).dispatch(request, *args, **kwargs)

urls.py

url(r'^(?P<quiz_name>[\w-]+)/startquiz/$',view=QuizTakeAutoAuth.as_view(), name='quiz_question_auth'),

What am I missing here? I am using the same view elsewhere without any knox Tokenauthentication and works as expected.

Answer 1

Since you're using a paramater quiz_name in the url , it is being passed to your corresponding view. The current signature of your get method doesn't accept any additional parameters.

You may fix this by changing the method signature to:

def get(self, request, *args, **kwargs):
    quiz_name = kwargs.get('quiz_name')
    ...