[英]Modify copied array without modifying the original array js
function checkCashRegister(price, cash, cid) {
let payBackAmount = cash - price;
let tempArr = cid.slice();
for (let i = 0; i < tempArr.length; i++) {
tempArr[i][1] = 0;
}
console.log("cid is", cid);
}
checkCashRegister(19.5, 20, [
["PENNY", 1.01],
["NICKEL", 2.05],
["DIME", 3.1],
["QUARTER", 4.25],
["ONE", 90],
["FIVE", 55],
["TEN", 20],
["TWENTY", 60],
["ONE HUNDRED", 100],
]);
Here I am trying to copy an array from the parameterized function.在这里,我试图从参数化的 function 中复制一个数组。
cid
is the array which I am trying to pass inside the function and I am trying to copy it into tempArr
. cid
是我试图在 function 中传递的数组,我试图将它复制到tempArr
中。 Later when modifying the values of tempArr
, the values of cid
is changing as well.稍后在修改
tempArr
的值时, cid
的值也会发生变化。 I have also tried copying the values using let tempArr=[...cid]
and let tempArr=cid.slice(0)
我也尝试使用
let tempArr=[...cid]
和let tempArr=cid.slice(0)
复制值
Here in the above code when you are copying one array to an other array the slice method and spread operator from javascript does a shallow copy, for your usecase you might want to do a deep clone of the object you can do let tempArr = JSON.parse(JSON.stringify(cid))
, instead of this you can also use deepClone
from Lodash to deep clone a object在上面的代码中,当您将一个数组复制到另一个数组时,javascript 中的切片方法和扩展运算符执行浅拷贝,对于您的用例,您可能想要对 object 进行深度克隆,您可以
let tempArr = JSON.parse(JSON.stringify(cid))
,您也可以使用deepClone
的 deepClone 来深度克隆 object
also please look at this thread What is the difference between a deep copy and a shallow copy?也请看这个线程深拷贝和浅拷贝有什么区别? to know more about shallow clone and deep clone
了解更多关于浅克隆和深克隆
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