迭代 python 中的二维列表并打印每个元素的标题

Question

I am trying to work out how to iterate over a list and print out each item with a print statement describing what element is. my project is to create a user management system and print out something similar to the image I have attached.

The output I am trying to produce

The output I am getting

My code:

records = 0
userFirst = ["John"]
userLast = ["Doe"]
autoUsername = ["Johndoe91"]
autoPassword = ["123456789"]
hiddenPassword = ["*****789"]
userRole = ["User"]
userDept = ["Administration"]
users = []  
confidentialUserDetails = []  

users.append(userFirst + userLast + userRole + userDept + autoUsername + autoPassword)
confidentialUserDetails.append(users)

for row in range(len(confidentialUserDetails)):
    records += 1
    print("-" * 25)
    print("Record: ", records)
    for col in range(len(confidentialUserDetails[row])):
        print(confidentialUserDetails[row][col])

Any help would be greatly appreciated. :)

Answer 1

I created a dictionary called user instead of your list and after that I appended it to the second list and finally I printed the key and the value of the dictionary.

Also to get the full name I joined userFirst and userLast as string.

Code:

records = 0
userFirst = ["John"]
userLast = ["Doe"]
autoUsername = ["Johndoe91"]
autoPassword = ["123456789"]
hiddenPassword = ["*****789"]
userRole = ["User"]
userDept = ["Administration"]

confidentialUserDetails = []  # 2d list for asterisked passwords

users={'Name' : [' '.join(userFirst + userLast)] ,'Role' : userRole , 'Departement' : userDept ,'Username' : autoUsername ,'Password' : hiddenPassword }
confidentialUserDetails.append(users)

for user in confidentialUserDetails:
    records += 1
    print("-" * 25)
    print("Record: ", records)
    for ele,v in user.items():
        print(ele,':',v[0])

Output:

-------------------------
Record:  1
Name : John Doe
Role : User
Departement : Administration
Username : Johndoe91
Password : *****789

Answer 2

Your data structures are unusual. I'm assuming that those lists are going to be provided to your code somehow and will, in practice, have multiple user details appended to them so that they are all the same length.

Anyhow, you can achieve the output you're looking for with some readable f-strings like this:

from functools import reduce

userFirst = ["John"]
userLast = ["Doe"]
autoUsername = ["Johndoe91"]
autoPassword = ["123456789"]
hiddenPassword = ["*****789"]
userRole = ["User"]
userDept = ["Administration"]

for row in range(len(userFirst)):
    s = (f"""\
Name          : {userFirst[row]} {userLast[row]}
Role          : {userRole[row]}
Department    : {userDept[row]}
Username      : {autoUsername[row]}
Password      : {hiddenPassword[row]}""")

    maxlen = reduce(lambda x,y: max(x, len(y)), s.split("\n"), 0)
    print(f"{s}\n{'-'*maxlen}\n")

Output:

Name          : John Doe
Role          : User
Department    : Administration
Username      : Johndoe91
Password      : *****789
------------------------------

Answer 3

Using a dictionary or f strings like the two other answers suggested is probably the best. But if you just want to use your current code to print your desired output, you can simply grab each item by its index number in your print statement.

Change the line:

print(confidentialUserDetails[row][col])

To something like this:

print("Name          : ", confidentialUserDetails[row][col][0], confidentialUserDetails[row][col][1])
print("Role:         : ", confidentialUserDetails[row][col][2])

Output:

-------------------------
Record:  1
Name          :  John Doe
Role:         :  User