如何使用 R 在不同列中查找非 NA 和 NA 的重叠数

Question

I am going to find the number of overlaps between some groups (arranged as columns of data set). In fact, I want to use these values to draw a venn diagram for my data. I require to count all non-NA values for each column and also the number of non-NA values overlapped between different columns (eg group 1 with group2 or group1, group2 and group4, ..........). The content of cells is not important and I am not looking for common cells between columns. I just want to count non-NAs regardless of their content. Do you have any idea to do it using R or python. example of part of data: structure(list(V1 = c("Group1", "XP_032738419.1", "XP_032715310.1", "XP_032703108.1", "XP_032700385.1", NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), V2 = c("Group2", "XP_011286297.1, XP_011286306.1, XP_019670819.1, XP_019670818.1, XP_023097752.1, XP_011286308.1, XP_011286311.1, XP_023097760.1, XP_011286303.1, XP_023097755.1, XP_023097756.1, XP_023097757.1, XP_023097758.1, XP_023097754.1, XP_023097753.1, XP_011286310.1, XP_023097759.1, XP_019670826.1, XP_011286304.1, XP_019670828.1", NA, "XP_019685915.1", "XP_023112367.1", NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), V3 = c("Group3", "XP_038528678.1", "XP_038300380.1", "XP_038538922.1", "XP_038295408.", NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), V4 = c("Group4", "XP_012903997.1", "XP_004748105.1, XP_012909429.1", "XP_012905661.1", "XP_012901919.1", NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), V5 = c("Group5", "NP_001310871.1", "NP_001341201.1", "N P_001374917.1", "NP_001123304.1", NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA), V6 = c("Group6", "XP_044098939.1", "XP_044080143.1", "XP_044112499.1", "XP_044084408.1", NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA)), row.names = c("1", "2", "3", "4", "5", "NA", "NA.1", "NA.2", "NA.3", "NA.4", "NA.5", "NA.6", "NA.7", "NA.8", "NA.9", "NA.10", "NA.11", "NA.12", "NA.13", "NA.14"), class = "data.frame")

Answer 1

The number of rows where both Group1 and Group2 are NA would be:

 sum( rowSums( is.na( dfrm[1:2]) ) == 2)

At least I hope it would be. is.na(.) applied to a dataframe (or subset of a dataframe as I attempt here) should return an equivalently dimensioned, logical dataframe and then you can test whether a rowSum of logicals (1=TRUE, 0=FALSE) is 2. Then you add them up. Regular R code is best read from the inside out as this demonstrates. The magrittr / tidyverse language variant of R reverses the arrangement of arguments and functions. You should still delete the image and post [MCVE], and ideally you would [edit] your question so that the clarifying information in your comment would be made available for persons searching for similar help.