R - 如果列包含来自向量的字符串，则 append 标志到另一列

Question

My Data

I have a vector of words, like the below. This is an oversimplification, my real vector is over 600 words:

myvec <- c("cat", "dog, "bird")

I have a dataframe with the below structure:

structure(list(id = c(1, 2, 3), onetext= c("cat furry pink british", 
"dog cat fight", "bird cat issues"), cop= c("Little Grey Cat is the nickname given to a kitten of the British Shorthair breed that rose to viral fame on Tumblr through a variety of musical tributes and photoshopped parodies in late September 2014", 
"Dogs have soft fur and tails so do cats Do cats like to chase their tails", 
"A cat and bird can coexist in a home but you will have to take certain measures to ensure that a cat cannot physically get to the bird at any point"
), text3 = c("On October 4th the first single topic blog devoted to the little grey cat was launched On October 20th Tumblr blogger Torridgristle shared a cutout exploitable image of the cat, which accumulated over 21000 notes in just over three months.", 
"there are many fights going on and this is just an example text", 
"Some cats will not care about a pet bird at all while others will make it its life mission to get at a bird You will need to assess the personalities of your pets and always remain on guard if you allow your bird and cat to interact"
)), class = c("tbl_df", "tbl", "data.frame"), row.names = c(NA, 
-3L))

It looks like the below picture

My issue

For each keyword on my vector myvec , I need to go around the dataset and check the columns onetext , cop , text3 , and if I find the keyword on either of those 3 columns, then I need to append the keyword into a new column. The result would be as the image as follows:

My original dataset is quite large (the last column is the longest), so doing multiple nested loops (which is what I tried) is not ideal.

EDIT: Note that as long as the word appears once in that row, that's enough and should be listed. All keywords should be listed.

How could I do this? I'm using tidyverse, so my dataset is actually a tibble .

Similar Posts (but not quite)

The following posts are somewhat similar, but not quite:

• If Column Contains String then enter value for that row
• R Column Check if Contains Value from Another Column
• Add new column if range of columns contains string in R

Answer 1

Here is how you could achieve the result:

1. create a pattern of the vector
2. use mutate across to check the needed columns
3. if the desired string is detected then extract to a new column !

myvec <- c("cat", "dog", "bird")

pattern <- paste(myvec, collapse="|")

library(dplyr)
library(tidyr)
df %>% 
  mutate(across(-id, ~case_when(str_detect(., pattern) ~ str_extract(., pattern)), .names = "new_col{col}")) %>% 
  unite(Match, starts_with('new'), na.rm = TRUE, sep = ',')

     id onetext                cop                                                                                       text3                                                                                                 Match   
  <dbl> <chr>                  <chr>                                                                                     <chr>                                                                                                 <chr>   
1     1 cat furry pink british Little Grey Cat is the nickname given to a kitten of the British Shorthair breed that ro~ On October 4th the first single topic blog devoted to the little grey cat was launched On October 20~ cat,cat 
2     2 dog cat fight          Dogs have soft fur and tails so do cats Do cats like to chase their tails                 there are many fights going on and this is just an example text                                       dog,cat 
3     3 bird cat issues        A cat and bird can coexist in a home but you will have to take certain measures to ensur~ Some cats will not care about a pet bird at all while others will make it its life mission to get at~ bird,ca~
> library(tidyr)