如何为不同的值列表连续获取唯一值？

Question

This is the query I have written:

select c.id, CONCAT(c.major_version, '.', c.minor_version) as versions
from event_ids c
where c_id in ('101') group by c_id, major_version, minor_version;

This is the result I am getting

id	versions
101	0.0
101	1.0
101	2.0
101	3.0

I am trying to get a single value against a list of different values for the same id.

id	versions
101	0.0
	1.0
	2.0
	3.0

How do I write the query so I get the desired result?

Answer 1

try this

select (case when rowNumber = 1 then c_id else null end) id, versions 
from (
    select ROW_NUMBER() OVER( PARTITION BY c.c_id ORDER BY major_version) as rowNumber, c.c_id, 
        CONCAT(c.major_version, '.', c.minor_version) as versions
    from event_ids c
    where c_id in ('101') group by c_id, major_version, minor_version
) tempTable

Answer 2

You could try

select case when c.major_version = 0 and c.minor_version = 0 then c.id else null 
end as id, 
CONCAT(c.major_version, '.', c.minor_version) as versions
from event_ids c
where c_id in ('101') group by c_id, major_version, minor_version;