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根据另一列的值创建新列

[英]Create new column based on value of another column

I have a solution below to give me a new column as a universal identifier, but what if there is additional data in the NAME column, how can I tweak the below to account for a wildcard like search term?我在下面有一个解决方案,可以给我一个新列作为通用标识符,但是如果 NAME 列中有其他数据怎么办,我如何调整下面的内容以说明像搜索词这样的通配符?

I want to basically have so if German/german or Mexican/mexican is in that row value then to give me Euro or South American value in new col我基本上想要如果德国/德国或墨西哥/墨西哥在该行值中,那么在新列中给我欧元或南美价值

    df["Identifier"] = (df["NAME"].str.lower().replace(
                             to_replace = ['german', 'mexican'], 
                             value = ['Euro', 'South American']
                           ))
    
    print(df)
          NAME      Identifier
    0   German            Euro
    1   german            Euro
    2  Mexican  South American
   3  mexican  South American




Desired output
            NAME             Identifier
    0    1990 German           Euro
    1   german 1998            Euro
    2  country Mexican     South American
    3  mexican city 2006   South American

Based on an answer in this post :基于这篇文章中的答案:

r = '(german|mexican)'

c = dict(german='Euro', mexican='South American')

df['Identifier'] = df['NAME'].str.lower().str.extract(r, expand=False).map(c)

Another approach would be using np.where with those two conditions, but probably there is a more ellegant solution.另一种方法是在这两个条件下使用np.where ,但可能有更优雅的解决方案。

below code will work.下面的代码将起作用。 i tried it using apply function but somehow can't able to get it.我尝试使用 apply function 但不知何故无法获得它。 probably in sometime.可能在某个时候。 meanwhile workable code below同时下面的可行代码

df3['identifier']=''
js_ref=[{'german':'Euro'},{'mexican':'South American'}]
for i in range(len(df3)):
    for l in js_ref:
        for k,v in l.items():
            if k.lower() in df3.name[i].lower():
                df3.identifier[i]=v
                break

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