在 Python 中，如何逐行读取文本文档并在每行末尾打印一行中相同字符的数量？

Question

I have a program which converts a simple image (black lines on white background) into 2 character ASCII art ("x" is black and "-" is white).

I want to read each line and print the number or same character in a row at the end of each line. Do you know how I can do this?

for example:

---x---  3 1 3
--xxx--  2 3 2
-xxxxx-  1 5 1

in the top row there are 3 dashes 1 'x' and 3 dashes, and so on. I would like these numbers to be saved to the ASCII text document.

Thank you!

Answer 1

You can use itertools.groupby :

from itertools import groupby

with open("art.txt", 'r') as f:
    for line in map(lambda l: l.strip(), f):
        runs = [sum(1 for _ in g) for _, g in groupby(line)]
        print(f"{line} {' '.join(map(str, runs))}")

# ---x--- 3 1 3
# --xxx-- 2 3 2
# -xxxxx- 1 5 1