[英]R - Number of observations per month in an xts object (weekday data)
I have several xts-objects containing weekday data from 2001-01-01 to 2021-12-31.我有几个 xts 对象,其中包含从 2001 年 1 月 1 日到 2021 年 12 月 31 日的工作日数据。 Now I need to know the number of observations within each month from January 2001 to December 2021 in order to further analyse them.现在我需要知道从 2001 年 1 月到 2021 年 12 月每个月的观察次数,以便进一步分析它们。 How can I get these?我怎样才能得到这些? I'm rather new to R (and programming), so I assume there is a simple formula for this I am unaware of.我对 R(和编程)相当陌生,所以我认为有一个我不知道的简单公式。
structure(c(6.5156, 6.5, 6.4531, 6, 5.8594, 5.8281, 5.8438, 5.8281,
5.8438, 5.8438, 5.8438, 5.7969), class = c("xts", "zoo"), .CLASS = "double", index = structure(c(978307200,
978393600, 978480000, 978566400, 978652800, 978912000, 978998400,
979084800, 979171200, 979257600, 979516800, 979603200), tzone = "UTC", tclass = "Date"), .Dim = c(12L,
1L))
First I convert your xts object to a dataframe.首先,我将您的 xts 对象转换为数据框。 After that you can create a month
column using month
from lubridate
and group_by
per month to summarise
the number of observations per month like this:之后,您可以使用month
来自lubridate
和group_by
的月份创建一个month
列,以summarise
每月的观察次数,如下所示:
library(dplyr)
library(lubridate)
data.frame(date = index(df), coredata(df)) %>%
mutate(month = month(date)) %>%
group_by(month) %>%
summarise(n = n())
Output:输出:
# A tibble: 1 × 2
month n
<int> <int>
1 1 12
In this case your data has 12 observations in January.在这种情况下,您的数据在一月份有 12 个观测值。
xts has all kinds of period.apply
functions you can use. xts 有各种period.apply
你可以使用的功能。 for monthly: apply.monthly
每月: apply.monthly
Based on your example if you want the sum / mean / n of observations:根据您的示例,如果您想要观察的总和/平均值/ n:
# sum
apply.monthly(my_xts, sum)
[,1]
2001-01-16 72.1564
# mean
apply.monthly(my_xts, mean)
[,1]
2001-01-16 6.013033
# n of records
# length works like sum or mean,
# but this is an example of how to use an anonymous function.
apply.monthly(my_xts, function(x) length(x))
[,1]
2001-01-16 12
xts always takes the last day of the period to show the information. xts 总是在期间的最后一天显示信息。
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