[英]How to extract floats from a string?
I am trying to extract float numbers from a string and after that they will be saved in an array.我正在尝试从字符串中提取浮点数,然后将它们保存在数组中。
Here's a code I found and even though I made the necessary changes it doesn't work:这是我找到的代码,即使我进行了必要的更改,它也不起作用:
#include <iostream>
#include <string>
using namespace std;
string a="2,134 43,54 22,334";
string b[30];
int found,i=0;
while(a!="\0"){
found=a,find("\t");
for(int f=0;f<found;f++){
b[i]+=a[f];
}
a.erase(0,found+1);
i++;
}
for(int d=0;d<i;d++){
cout<<b[d]<<endl;
}
return 0;
}
Don't parse the string like that.不要像那样解析字符串。 Just read the values in your desired locale , for example most non-English European locales like
de_DE.utf8
, ru_RU.utf8
, or it_IT.UTF-8
... You can even set different locales for different streams, so for example below I'm using the default system locale for std::cin
and a custom locale which uses :
as the radix point in std::cout
只需读取所需语言环境中的值,例如大多数非英语欧洲语言环境,如
de_DE.utf8
、 ru_RU.utf8
或it_IT.UTF-8
...您甚至可以为不同的流设置不同的语言环境,例如下面我'm 使用std::cin
的默认系统语言环境和使用:
作为std::cout
中的小数点的自定义语言环境
#include <iostream>
#include <sstream>
#include <locale>
#include <clocale>
#include <stdlib.h>
template <class charT, charT sep>
class punct_facet: public std::numpunct<charT> {
protected:
charT do_decimal_point() const { return sep; }
};
int main(int argc, char** argv) {
// Use default locale for most std streams
std::locale::global(std::locale(""));
// Use C locale with custom radix point for stdout
std::cout.imbue(std::locale(std::locale("C"), new punct_facet<char, ':'>));
std::stringstream str(argv[1]);
double d;
while (str >> d)
{
std::cout << d << '\n';
}
return 0;
}
In C++ std::locale("")
gives you the current system locale which is probably el_GR.UTF-8
in your case.在 C++ 中
std::locale("")
为您提供当前系统语言环境,在您的情况下可能是el_GR.UTF-8
。 You can also specify a specific locale to use such as std::locale("fr_FR.utf8")
.您还可以指定要使用的特定语言环境,例如
std::locale("fr_FR.utf8")
。 Then use std::locale::global
to set the obtained locale globally.然后使用
std::locale::global
设置获取的语言环境。 Each specific stream can further be imbue
d to a different locale if necessary.如果需要,每个特定的流可以进一步被
imbue
到不同的语言环境。 You can also use setlocale
for setting some locale preferences您还可以使用
setlocale
设置一些区域设置首选项
Sample output:样本输出:
$ g++ read_locale.cpp -o read_locale
$ LC_ALL=el_GR.UTF-8 ./read_locale "2,134 43,54 22,334"
2:134
43:54
22:334
$ LC_ALL=en_US.utf8 ./read_locale "2.134 43.54 22,334"
2:134
43:54
22334
Notice the difference in the last output?注意到最后一个输出的不同了吗? That's because
,
is the thousand separator in the English locale那是因为
,
是英语语言环境中的千位分隔符
In the example above I'm setting the current locale via LC_ALL
, but on Windows you can't change that easily from the console so just do that in your code.在上面的示例中,我通过
LC_ALL
设置当前语言环境,但在 Windows 上,您无法从控制台轻松更改,因此只需在代码中执行此操作即可。 And I'm printing the output directly but pushing it into an array is trivial我直接打印输出但是将它推入数组是微不足道的
Note that those online platforms don't have a non-US locale so I have to use the custom locale.请注意,这些在线平台没有非美国语言环境,因此我必须使用自定义语言环境。 On Linux you can check the available locales with
locale -a
在 Linux 上,您可以使用
locale -a
检查可用的语言环境
In case you really want to get the floating-point numbers as strings (why?) then just read normally.如果您真的想将浮点数作为字符串(为什么?)然后正常读取。 No need for such complex parsing.
不需要如此复杂的解析。
std::cin
and any kinds of istream
will just stop at blank spaces as expected std::cin
和任何类型的istream
都会按预期停在空白处
#include <iostream>
#include <sstream>
#include <string>
int main(int argc, char** argv) {
std::stringstream str(argv[1]);
std::string s;
while (str >> s)
{
std::cout << s << '\n';
}
return 0;
}
Sample output:样本输出:
$ g++ read_numbers_as_string.cpp -o read_numbers_as_string
$ ./read_numbers_as_string "2,134 43,54 22,334"
2,134
43,54
22,334
If you don't care about performance that much, you can use this simple algorithm :如果你不太关心性能,你可以使用这个简单的算法:
#include <iostream>
#include <vector>
int main()
{
std::string a = "2,134 43,54 22,334";
std::vector<std::string> floats; // I used vector instead of array - easier and safer
std::string buffer;
for (auto& itr : a)
{
if (itr == ' ') // space -- float ended
{
floats.push_back(buffer);
buffer.erase();
}
else
{
buffer += itr;
}
}
if (!buffer.empty()) // if something left in the buffer -> push it
floats.push_back(buffer);
// printing 'floats' array
for (auto& itr : floats)
std::cout << itr << '\n';
return 0;
}
this algorithm goes through every char inside 'a' and checks:该算法遍历“a”中的每个字符并检查:
if you want me to explain someting feel free to ask :)如果你想让我解释一下,请随时问:)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.