已清理的消息，仅包含字母 az 和数字 0-9，只有一个空格

Question

cleaned message, which contains only letters az, and numbers 0-9, with only one space between words

def clean_data(message):
    return " ".join("".join(re.findall("[a-zA-Z0-9_ ]", message)).lower().split())

sentence_1 = 'Doesn\'t get, how{to}% \\operate+66.7 :after[it]"" & lt;# & gt; won\'t `or(what)'
sentence_2 = 'O\]k,.lar7i$double{} check wif*& da! hair: [dresser;   ..already He SaID-77.88.5 wun cut v short question(std txt rate)T&C\'s'

cleaned:  doesnt get howto operate667 afterit lt gt wont orwhat
cleaned:  oklar7idouble check wif da hair dresser already he said77885 wun cut v short questionstd txt ratetcs

Expected Output:

cleaned:    doesn t get how to operate 66 7 after it lt gt won t or what
cleaned:    o k lar7i double check wif da hair dresser already he said 77 88 5 wun cut v short question std txt rate t c s

Answer 1

From what you have posted we can deduce a couple of things:

• Output should have alphanumeric characters only
• Everything that wasn't an alphanumeric character get's replaced with a whitespace
• We shouldn't have multiple spaces next to each other
• Output is lowercase only

Assuming that's the expected behavior, the code is very straight forward:

def clean_data(message):
    return re.sub(r"[^\w]+", " ", message).lower()

1. You're getting chunks of unwanted characters with [^\w]+ and replacing them with a singular whitespace with the help of re.sub() .

2. We convert everything to lowercase with.lower()

---

sentence_1 = 'Doesn\'t get, how{to}% \\operate+66.7 :after[it]"" & lt;# & gt; won\'t `or(what)'
sentence_2 = 'O\]k,.lar7i$double{} check wif*& da! hair: [dresser;   ..already He SaID-77.88.5 wun cut v short question(std txt rate)T&C\'s'

print(clean_data(sentence_1))
print(clean_data(sentence_2))

>>> doesn t get how to operate 66 7 after it lt gt won t or what 
>>> o k lar7i double check wif da hair dresser already he said 77 88 5 wun cut v short question std txt rate t c s