Python计数0-9然后是az

Question

I'm attempting to build a style sheet with this structure:

.something-[content_name]:before {
  content: '[unicode_string]';
}

For the style sheet, the Unicode string follows the pattern:

/f[0-9a-z][0-9a-z][0-9a-z]

And a set of SVGs with this structure:

<glyph unicode="[unicode_string]" d="some_path" />

I have a list of things that I'm going to be inserting as content, and I need a way to iterate through and assign unicode values to the content.

I want to iterate through 0-9 then az (lowercase only) in each place before moving to the next, resulting in:

&#xf000, &#xf001, &#xf002 ... &#xf009
&#xf00a, &#xf00b, &#xf00c ... &#xf00z
&#xf010, &#xf011, &#xf012 ... &#xf019, &#xf01a, &#xf01b, &#xf01c ... &#xf01z
&#xf0a0, &#xf0b1, &#xf0 ... &#xf019, &#xf01a, &#xf01b, &#xf01c ... &#xf01z

Substituting / for &#x isn't an issue, I just want to know the best way to iterate through this way.

Answer 1

Are you looking for itertools.product?

import string, itertools


for p in itertools.product(string.digits + string.ascii_lowercase, repeat=3):
    print '&#xf' + ''.join(p)

For hex numbers, simply iterate over 0123456789abcdef :

for p in itertools.product('0123456789abcdef', repeat=3):