[英]Get function name and code inside function with regex
I am developing an application that reads and visualizes the entered codes.我正在开发一个应用程序来读取和可视化输入的代码。
#[account]
pub struct Tweet {
pub author: Pubkey,
pub timestamp: i64,
pub topic: String,
pub content: String,
}
I'm trying to get the struct name and the structures in it我正在尝试获取结构名称和其中的结构
const stringCode = `
#[account]
pub struct Tweet {
pub author: Pubkey,
pub timestamp: i64,
pub topic: String,
pub content: String,
}
`;
const functionRegexp =
/(pub struct\s+)(?<name>[$_\p{ID_Start}][$\u200c\u200c\p{ID_Continue}]*)/u;
const parseCode = () => {
const match = functionRegexp.exec(stringCode);
return parseCode;
};
I can see Tweet
name in match.groups.name
, but我可以在
match.groups.name
中看到Tweet
文名称,但是
pub author: Pubkey,
pub timestamp: i64,
pub topic: String,
pub content: String,
if i want to get this data?如果我想得到这些数据? thanks!
谢谢!
You can use this regex to group the struct name and the code inside brackets:您可以使用此正则表达式对结构名称和括号内的代码进行分组:
/pub struct (\w+)|(?<= )((?:.|\s)+)(?=$)/gm
pub struct (\w+)
match the struct name pub struct (\w+)
匹配结构名称
|
the or(|) split the expression, the second expression starts from the first one. or(|)拆分表达式,第二个表达式从第一个开始。
(?<= )((?:.|\s)+)(?=$)
match the code inside struct. (?<= )((?:.|\s)+)(?=$)
匹配结构中的代码。 Starting from the space after the struct name (?<= )
match all characters ((?:.|\s)+)
until reach the end of string (?=$)
.从结构名称
(?<= )
之后的空格开始匹配所有字符((?:.|\s)+)
直到到达字符串(?=$)
的末尾。
This will parse and return the name and the data structure:这将解析并返回名称和数据结构:
const stringCode = ` #[account] pub struct Tweet { pub author: Pubkey, pub timestamp: i64, pub topic: String, pub content: String, } `; const functionRegexp = /\bpub\s+struct\s+([$_\p{ID_Start}][$\p{ID_Continue}]*)\s*\{\s*([^\{]*?)\s*\}/u; const match = functionRegexp.exec(stringCode); console.log('name: ' + match[1]); console.log('data:\n' + match[2]);
name: Tweet data: pub author: Pubkey, pub timestamp: i64, pub topic: String, pub content: String,
Explanation:解释:
\bpub\s+struct\s+
- expect pub struct
with word boundary \bpub\s+struct\s+
- 期望带有单词边界的pub struct
([$_\p{ID_Start}][$\p{ID_Continue}]*)
- capture group 1 for name ([$_\p{ID_Start}][$\p{ID_Continue}]*)
- 捕获名称组 1\s*\{\s*
- expect optional whitespace, {
, optional whitespace \s*\{\s*
- 期望可选空格, {
,可选空格([^\{]*?)
- capture group 2 for data: anything non-greedily that is not {
([^\{]*?)
- 捕获第 2 组数据:任何非贪婪的不是{
\s*\}
- expect optional whitespace and }
\s*\}
- 期望可选的空格和}
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