Get function name and code inside function with regex

Question

I am developing an application that reads and visualizes the entered codes.

#[account]
pub struct Tweet {
pub author: Pubkey,
pub timestamp: i64,
pub topic: String,
pub content: String,
}

I'm trying to get the struct name and the structures in it

const stringCode = `
#[account]
pub struct Tweet {
pub author: Pubkey,
pub timestamp: i64,
pub topic: String,
pub content: String,
}
`;

const functionRegexp =
  /(pub struct\s+)(?<name>[$_\p{ID_Start}][$\u200c\u200c\p{ID_Continue}]*)/u;

const parseCode = () => {
  const match = functionRegexp.exec(stringCode);
  return parseCode;
};

I can see Tweet name in match.groups.name , but

pub author: Pubkey,
pub timestamp: i64,
pub topic: String,
pub content: String,

if i want to get this data? thanks!

Answer 1

You can use this regex to group the struct name and the code inside brackets:

/pub struct (\w+)|(?<= )((?:.|\s)+)(?=$)/gm

pub struct (\w+) match the struct name

| the or(|) split the expression, the second expression starts from the first one.

(?<= )((?:.|\s)+)(?=$) match the code inside struct. Starting from the space after the struct name (?<= ) match all characters ((?:.|\s)+) until reach the end of string (?=$) .

Answer 2

This will parse and return the name and the data structure:

 const stringCode = ` #[account] pub struct Tweet { pub author: Pubkey, pub timestamp: i64, pub topic: String, pub content: String, } `; const functionRegexp = /\bpub\s+struct\s+([$_\p{ID_Start}][$\p{ID_Continue}]*)\s*\{\s*([^\{]*?)\s*\}/u; const match = functionRegexp.exec(stringCode); console.log('name: ' + match[1]); console.log('data:\n' + match[2]);

Output:

 name: Tweet data: pub author: Pubkey, pub timestamp: i64, pub topic: String, pub content: String,

Explanation:

• \bpub\s+struct\s+ - expect pub struct with word boundary
• ([$_\p{ID_Start}][$\p{ID_Continue}]*) - capture group 1 for name
• \s*\{\s* - expect optional whitespace, { , optional whitespace
• ([^\{]*?) - capture group 2 for data: anything non-greedily that is not {
• \s*\} - expect optional whitespace and }