按 Pandas 中的多列求和分组（忽略重复项）

Question

I have the following code where my dataframe contains 3 columns

  toBeSummed toBeSummed2 toBesummed3  someColumn
0          X           X           Y         NaN
1          X           Y           Z         NaN
2          Y           Y           Z         NaN
3          Z           Z           Z         NaN

oneframe = pd.concat([df['toBeSummed'],df['toBeSummed2'],df['toBesummed3']], axis=1).reset_index()


temp = oneframe.groupby(['toBeSummed']).size().reset_index()
temp2 = oneframe.groupby(['toBeSummed2']).size().reset_index()
temp3 = oneframe.groupby(['toBeSummed3']).size().reset_index()
temp.columns.values[0] = "SameName"
temp2.columns.values[0] = "SameName"
temp3.columns.values[0]  = "SameName"

final = pd.concat([temp,temp2,temp3]).groupby(['SameName']).sum().reset_index()
final.columns.values[0] = "Letter"
final.columns.values[1] = "Sum"

The problem here is that with the code I have, it sums up all instances of each value. Meaning calling final would result in

  Letter  Sum
0      X    3
1      Y    4
2      Z    5

However I want it to not count more than once if the same value exists in the row (Ie in the first row there are two X's so it would only count the one X) Meaning the desired output is

  Letter  Sum
0      X    2
1      Y    3
2      Z    3

I can update or add more comments if this is confusing.

Answer 1

Given df :

  toBeSummed toBeSummed2 toBesummed3  someColumn
0          X           X           Y         NaN
1          X           Y           Z         NaN
2          Y           Y           Z         NaN
3          Z           Z           Z         NaN

Doing:

sum_cols = ['toBeSummed', 'toBeSummed2', 'toBesummed3']

out = df[sum_cols].apply(lambda x: x.unique()).explode().value_counts()
print(out.to_frame('Sum'))

Output:

   Sum
Y    3
Z    3
X    2