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R 如何根据其他 2 列将另一列添加到数据集

[英]R how to add another column to a dataset based on 2 other columns

I have a data set of messages exchanged in an organization, I want to create another column based on case_when the sender_department == receiver_department , assign "intra" while if the sender_department != receiver_department , assign "inter" .我有一个组织中交换的消息数据集,我想根据case_when sender_department == receiver_department创建另一个列,分配"intra"而如果sender_department != receiver_department ,则分配"inter"

I'm doing this to know the proportion of inter and intra departmental messages over the period.我这样做是为了了解在此期间部门间和部门内消息的比例。

I've use the code below我使用下面的代码

intra_inter_msg <- DF %>%
  mutate(inter_intra = case_when(sender_department == receiver_department, ~"intra",         ,
                                 sender_department != receiver_department, ~"inter"))

and I got this error我得到了这个错误

Error in mutate() : mutate()错误:
! Problem while computing inter_intra = case_when(...) .计算inter_intra = case_when(...)时出现问题。 Caused by error in case_when() :case_when()中的错误引起:
! Case 1 ( sender_department == receiver_department ) must be a two-sided formula, not a logical情况 1 ( sender_department == receiver_department ) 必须是双面公式,而不是逻辑

I made a little example DF to test it:我做了一个小例子 DF 来测试它:

require(dplyr)
DF = data.frame (sender_department = c("econ","math","history"),receiver_department = c("econ","history","math"))
DF
intra_inter_msg <- DF %>%
  mutate(inter_intra = case_when(sender_department == receiver_department ~"intra",         
                                 sender_department != receiver_department ~"inter"))
intra_inter_msg

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