使用BufferedImage从Java中获取RGB colourspace的灰度像素值

Question

Anyone know of a simple way of converting the RGBint value returned from <BufferedImage> getRGB(i,j) into a greyscale value?

I was going to simply average the RGB values by breaking them up using this;

int alpha = (pixel >> 24) & 0xff;
int red = (pixel >> 16) & 0xff;
int green = (pixel >> 8) & 0xff;
int blue = (pixel) & 0xff;

and then average red,green,blue.

But i feel like for such a simple operation I must be missing something...

After a great answer to a different question, I should clear up what i want.

I want to take the RGB value returned from getRGB(i,j), and turn that into a white-value in the range 0-255 representing the "Darkness" of that pixel.

This can be accomplished by averaging and such but I am looking for an OTS implementation to save me a few lines.

Answer 1

This tutorial shows 3 ways to do it:

By changing ColorSpace

ColorSpace cs = ColorSpace.getInstance(ColorSpace.CS_GRAY);
ColorConvertOp op = new ColorConvertOp(cs, null);
BufferedImage image = op.filter(bufferedImage, null);

By drawing to a grayscale BufferedImage

BufferedImage image = new BufferedImage(width, height,
    BufferedImage.TYPE_BYTE_GRAY);
Graphics g = image.getGraphics();
g.drawImage(colorImage, 0, 0, null);
g.dispose();

By using GrayFilter

ImageFilter filter = new GrayFilter(true, 50);
ImageProducer producer = new FilteredImageSource(colorImage.getSource(), filter);
Image image = this.createImage(producer);

Answer 2

this isn't as simple as it sounds because there is no 100% correct answer for how to map a colour to greyscale.

the method i'd use is to convert RGB to HSL then 0 the S portion (and optionally convert back to RGB) but this might not be exactly what you want. (it is equivalent to the average of the highest and lowest rgb value so a little different to the average of all 3)

Answer 3

Averaging sounds good, although Matlab rgb2gray uses weighted sum.

Check Matlab rgb2gray

UPDATE
I tried implementing Matlab method in Java, maybe i did it wrong, but the averaging gave better results.