如何从Python中的异常对象获取堆栈跟踪？

Question

How can I get the full stack trace from the Exception object itself?

Consider the following code as reduced example of the problem:

last_exception = None
try:
    raise Exception('foo failed')
except Exception as e:
    last_exception = e
# this happens somewhere else, decoupled from the original raise
print_exception_stack_trace(last_exception)

Answer 1

Edit: I lied, sorry. e.__traceback__ is what you want.

try:
    raise ValueError
except ValueError as e:
    print( e.__traceback__ )

>c:/python31/pythonw -u "test.py"
<traceback object at 0x00C964B8>
>Exit code: 0

This is only valid in Python 3; you can't do it in earlier versions.