在Java中使用正则表达式将字符串分成两个用冒号分隔的字符串，并忽略标记和引号内的冒号

Question

I have been trying to figure out a Java RegEx for some while now that would split something like the following into two pieces:
l&<6:98>9"hello:world"-45:&<78:89>"hedhed:hdeh"+56 it should be split at the colon after "-45" ignoring all colons inside tags and quotes. Neither of the sides must not necessarily contain any tags or quotes.

Help would be greatly appreciated :)

Answer 1

This would be a starting point for a parsing function:

/** example: findCharIndex(subject, ':'); */
public static int findCharIndex(String subject, char findChar)
{
    boolean insideQuotes = false;
    boolean insideTags = false;
    for (int index = 0; index < subject.length(); index++)
    {
        char ch = subject.charAt(index);
        if (ch == '"')
            insideQuotes = !insideQuotes;
        else if (!insideQuotes)
        {
            if (ch == '<')
                insideTags = true;
            else if (insideTags && ch == '>')
                insideTags = false;
        }
        if (!insideQuotes && !insideTags && ch == findChar)
            return index;
    }
    return -1;
}

Answer 2

执行匹配比拆分更容易。

(?:[^"<:]|"[^"]*"|<[^>]*)*