[英]Transform XML from old schema to new schema?
I need to transform an XML document which does not use any schema to another format which uses a well defined schema. 我需要将不使用任何模式的XML文档转换为使用定义良好的模式的另一种格式。
So basically I have to transform this: 因此,基本上我必须对此进行转换:
<healthCareFacilityTypeCode
displayName="Home"
codingScheme="Connect-a-thon healthcareFacilityTypeCodes"
>Home</healthCareFacilityTypeCode>
Into this: 变成这个:
<healthCareFacilityTypeCode>
<code>Home</code>
<displayName>
<LocalizedString value="Home" />
</displayName>
<schemeName>Connect-a-thon healthcareFacilityTypeCodes</schemeName>
</healthCareFacilityTypeCode>
I know how to transform it by hand by looking at the schema. 我知道如何通过查看架构来手动转换它。 Here is a snippet of the XSD:
这是XSD的片段:
<xsd:complexType name="DocumentEntryType">
<xsd:sequence>
<xsd:element minOccurs="0"
name="healthCareFacilityTypeCode"
type="tns:CodedMetadataType"/>
</xsd:sequence>
<xsd:attribute default="false"
name="existing"
type="xsd:boolean"
use="optional"/>
</xsd:complexType>
<xsd:element name="DocumentEntry" type="tns:DocumentEntryType"/>
What I don't know how to tackle is: how to exploit the target XSD to transform a node from the source XML to the target XML doc. 我不知道如何解决:如何利用目标XSD将节点从源XML转换为目标XML文档。 I feel all the info to perform the transform is located in the XSD but can I use it?
我觉得执行转换的所有信息都位于XSD中,但是我可以使用它吗? how?
怎么样?
Any help will be greatly appreciated! 任何帮助将不胜感激!
Followed suggestions and this is what I came up with. 遵循建议,这就是我的想法。 Not perfect but it is enough for my purpose.
虽然不完美,但足以满足我的目的。
<xsl:template match="XDSDocumentEntry">
<DocumentEntryType>
<xsl:call-template name="namespaceChange"/>
<xsl:apply-templates/>
</DocumentEntryType>
</xsl:template>
<xsl:template match="node() | @*">
<xsl:copy>
<xsl:apply-templates select="node() | @*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="//*[matches(name(), 'Code')]">
<xsl:copy>
<code>
<xsl:value-of select="."/>
</code>
<schemeName>
<xsl:value-of select="@codingScheme"/>
</schemeName>
<displayName>
<LocalizedString>
<xsl:attribute name="value">
<xsl:value-of select="@displayName"/>
</xsl:attribute>
</LocalizedString>
</displayName>
</xsl:copy>
</xsl:template>
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