如何在C＃程序中获取小数到n位精度的Pi

Question

With reg to this question Pi in C#

I coded the below code and gives a output with last 6 digits as 0. So I want to improve the program by converting everything to decimal. I have never used decimal in C# instead of a double before and I am only comfortable with double in my regular use.

So please help me with decimal conversion, i tried to replace all double to decimal at start and it didnt turn good :(.

 using System;

class Program
{
    static void Main()
    {
    Console.WriteLine(" Get PI from methods shown here");
    double d = PI();
    Console.WriteLine("{0:N20}",
        d);

    Console.WriteLine(" Get PI from the .NET Math class constant");
    double d2 = Math.PI;
    Console.WriteLine("{0:N20}",
        d2);
    }

    static double PI()
    {
    // Returns PI
    return 2 * F(1);
    }

    static double F(int i)
    {
    // Receives the call number
   //To avoid so error
    if (i > 60)
    {
        // Stop after 60 calls
        return i;
    }
    else
    {
        // Return the running total with the new fraction added
        return 1 + (i / (1 + (2.0 * i))) * F(i + 1);
    }
    }
}

Output

Get PI from methods shown here 3.14159265358979000000 Get PI from the .NET Math class constant 3.14159265358979000000

Answer 1

Well, replacing double with decimal is a good start - and then all you need to do is change the constant from 2.0 to 2.0m:

static decimal F(int i)
{
    // Receives the call number
    // To avoid so error
    if (i > 60)
    {
        // Stop after 60 calls
        return i;
    }
    else
    {
        // Return the running total with the new fraction added
        return 1 + (i / (1 + (2.0m * i))) * F(i + 1);
    }
}

Of course it's still going to have limited precision, but slightly more than double . The result is 3.14159265358979325010 .