获取第一个节点的节点值

Question

I have the following XML:

<?xml version='1.0' ?>
<foo>A&gt;B</foo>

and just want to get the node value of start tag as A>B , if we use getNodeValue it will convert it to A>B which is not needed.

Hence I decided to use the Transformer

        Document doc = getParsedDoc(abovexml);
        TransformerFactory tranFact = TransformerFactory.newInstance();
        Transformer transfor = tranFact.newTransformer();
        transfor.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
        Source src = new DOMSource(node);
        StringWriter buffer = new StringWriter();
        Result dest = new StreamResult(buffer);
        transfor.transform(src, dest);
        String result = buffer.toString();

But this gives the following output as part of result as <foo>A&gt;B</foo>

It will be helpful if somebody could clarify, if there is an approach with which we can get A>B without doing string manipulation from the above output ( <foo>A&gt;B</foo> )

Answer 1

Since getNodeValue() is automatically decoding the the String.
You can use StringEscapeUtils from Apache Commons Lang to encode it again.

http://commons.apache.org/lang/api-2.6/org/apache/commons/lang/StringEscapeUtils.html
http://commons.apache.org/lang/

String nodeValue = StringEscapeUtils.escapeHtml(getNodeValue());

That would encode it into the format you want it to be in. It is not very performance friendly because you are applying encode for every node value.

Answer 2

Actually getNodeValue() is not "converting" the string. When the XML is parsed from a file, or produced by a transformation, the resulting information model is that the string is A>B , not A>B . The latter is just a serialization form.

Another legitimate serialization form is A>B (because right angle bracket does not need to be escaped in most cases ). However, there may be compatibility reasons for wanting to produce A>B , especially if your output is intended to be HTML (though you didn't mention that).

If you have a good reason for escaping the > , then I agree with @kensen john's answer for getting that done.