使用sed删除行直到文件结尾

Question

I'm using sed -n '/[test1]/,/[test2]/{/[test2]/!p}' test.txt > temp.txt ..which works well if If I only want the top selection, but I'm after the bottom section.

[test1]
A
B
C
[test2]
1
2
3

But I'm after [test2] onwards, so Copying [test2] till the end of the line. So producing an output like so,

[test2]
1
2
3

Answer 1

Try this command:

sed -n  '/\(^\[test2\]\)/,$p' test.txt > temp.txt

Edit :

With extended regular expression flag( -r ),

 sed -n -r '/(^\[test2\])/,$p' test.txt > temp.txt

Answer 2

Yes, grep -n will output the line number and match, and processing it I came up with the following

 grep -n '\[test2\]' temp.txt | awk -F\: '{print "sed \"1,"$1-1"d;\" temp.txt"}' | bash > test.txt

so a cat of the new file produces the following:

 cat test.txt
 [test2]
 1
 2
 3

btw, | bash | bash redirects formatted command lines with awk to bash in order to execute them