[英]Instantiating a generic extension of an abstract class
Trying to write some generalised code for Genetic Algorithms and I have an abstract class Genotype as follows: 试图为遗传算法编写一些通用代码,我有一个抽象类基因型如下:
public abstract class Genotype {
private ArrayList<Gene> genotype = new ArrayList<Gene>();
//...
public Genotype(ArrayList<Gene> genotype) {
setGenotype(genotype);
setGenotypeLength(genotype.size());
}
public abstract Phenotype<Gene> getPhenotype();
public abstract void mutate();
//...
}
This class is intended to be extended and the subclass obviously provides the implementation of getPhenotype() and mutate(). 该类旨在扩展,子类显然提供了getPhenotype()和mutate()的实现。 However, I also have a second class that takes two Genotype objects as parameters and returns an ArrayList containing Genotype objects.
但是,我还有一个第二个类,它接受两个Genotype对象作为参数,并返回一个包含Genotype对象的ArrayList。 Since I don't know the type of the extended Genotype objects at this point I need to use a generic parameter as follows:
由于此时我不知道扩展的Genotype对象的类型,我需要使用泛型参数,如下所示:
public class Reproducer {
//...
private <G extends Genotype> ArrayList<Genotype> crossover(G parent1, G parent2) {
ArrayList<Genotype> children = new ArrayList<Genotype>();
ArrayList<Gene> genotypeOne = ArrayListCloner.cloneArrayList(parent1.getGenotype());
ArrayList<Gene> genotypeTwo = ArrayListCloner.cloneArrayList(parent2.getGenotype());
//one point crossover
int p = gen.nextInt(genotypeOne.size());
for (int i = 0; i < p; i++) {
genotypeOne.set(i, genotypeOne.get(i));
genotypeTwo.set(i, genotypeTwo.get(i));
}
for (int i = p; i < 10; i++) {
genotypeOne.set(i, genotypeTwo.get(i));
genotypeTwo.set(i, genotypeOne.get(i));
}
children.add(new G(genotypeOne)); //THROWS ERROR: Cannot instantiate the type G
children.add(new G(genotypeTwo)); //THROWS ERROR: Cannot instantiate the type G
return children;
}
}
However, since I need to return two objects of type G in an ArrayList I clearly have a problem where I can't instantiate the new Genotype objects because they're 1. generic types and presumably 2. abstract. 但是,由于我需要在ArrayList中返回两个G类型的对象,我显然遇到了一个问题,我无法实例化新的Genotype对象,因为它们是1.泛型类型,大概是2. abstract。
This might be a bad way of going about things all together but if anyone has a solution that would be great. 这可能是将所有事情放在一起的坏方法,但如果有人有一个很好的解决方案。 Thank you.
谢谢。
I would suggesting using a factory method in your Genotype
class 我建议你在
Genotype
类中使用工厂方法
public abstract class Genotype {
public abstract GenoType newInstance();
}
You could use an abstract factory pattern . 您可以使用抽象工厂模式 。 Since you need only one factory method in your factory this is arguably a degenerate case, but it might be what you need.
由于您的工厂只需要一种工厂方法,这可以说是一种退化的情况,但它可能就是您所需要的。 You should pass the factory instance to your
Reproducer
object, probably as a an argument of some method. 您应该将工厂实例传递给
Reproducer
对象,可能作为某种方法的参数。 It's not pretty, but at least you now have abstraction over object creation. 它并不漂亮,但至少你现在拥有对象创建的抽象概念。
A better solution would probably be to change your architecture. 更好的解决方案可能是改变您的架构。 Why not forget about the
Genotype
class? 为什么不忘记
Genotype
类呢? Your genotype representation is basically a list of genes. 您的基因型表示基本上是基因列表。 You could make a utility class with (generic) operations on these lists and use these operations in your other classes.
您可以在这些列表上创建具有(通用)操作的实用程序类,并在其他类中使用这些操作。 The following is a sketch of what I mean:
以下是我的意思草图:
public static <G extends Gene> List<? extends G> mutate( List<G> genotype ) { ... }
public static <G extends Gene> List<List<? extends G>> crossover( List<G> p1, List<G> p2 ) { ... }
As a side note: favour declaring interface types over class types; 作为旁注:赞成在类类型上声明接口类型; in your example you don't use the
List
interface. 在您的示例中,您不使用
List
接口。
As a final side note: in your example you don't really need the generic type. 最后一点注意:在您的示例中,您并不真正需要泛型类型。 If you declare the parameter types as
Genotype
you get the same solution (with the same problem). 如果将参数类型声明为
Genotype
则会得到相同的解决方案(具有相同的问题)。 A type X parameter accepts any object of type X (including subtypes!) as argument. 类型X参数接受任何类型为X的对象(包括子类型!)作为参数。
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