当我在顶点着色器中有一个“ out”时，OpenGL无法绘制

Question

I have aa vertex shader and a fragment shader. I am sending in a color variable in the buffer to the vertex shader, and then trying to pass it to the fragment shader. When I have an out vec4 out_color in my code, nothign is drawn. My code is

"in vec4 in_position;\n"
"in vec4 in_color;\n"
"out vec4 out_color;"
"void\nmain()\n"
"{\n"
"  gl_Position = in_position;\n"
"out_color = in_color;"
"}\n\n";

Can anyone shed some light on this?

Answer 1

You forgot the newline after the declaration of out_color in your shader string. So it is on the same line as void main() (in which you also have a newline, but that might not be a problem).

For the sake of clarity, I would suggest you to always use one substring for a single line and always include a newline at the end of each substring, if you really want to use in-code shader code, anyway.

And you should also always check if your shaders compiled correctly and the program linked correctly and query the info log in case they didn't. This would have told you the error quite obviously (or at least would have given you a hint).

Answer 2

原来我使用的着色语言版本错误，必须在两个着色器的顶部都包含代码

#version 140;