[英]Matlab filter() with SciPy lfilter()
According to their documentation for Matlab filter() and SciPy lfilter() , it seems like they should be "compatible". 根据他们对Matlab filter()和SciPy lfilter()的文档,看起来它们应该是“兼容的”。 However I have a problem, porting larger Matlab code in Python, for which I get ValueError: object of too small depth for desired array
. 但是我有一个问题,在Python中移植更大的Matlab代码,我得到了ValueError: object of too small depth for desired array
。 As I can't think of how I can present my source without complicating it, I'll use the example provided in Matlab's documentation: 由于我无法想象如何在不使其复杂化的情况下呈现我的源代码,我将使用Matlab文档中提供的示例:
data = [1:0.2:4]';
windowSize = 5;
filter(ones(1,windowSize)/windowSize,1,data)
which I translate in Python to: 我在Python中翻译为:
import numpy as np
from scipy.signal import lfilter
data = np.arange(1, 4.1, 0.2)
windowSize = 5
lfilter(np.ones((1, windowSize)) / windowSize, 1, data)
In this case I get: 在这种情况下,我得到:
ValueError: object too deep for desired array
Why do I get these errors? 为什么我会收到这些错误?
Is there a reason you're adding a an extra dimension when creating your array of ones? 您是否有理由在创建数组时添加额外的维度? Is this what you need: 这是你需要的:
lfilter(np.ones(windowSize) / windowSize, 1, data)
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