[英]Flip an array of Cellular Automata data into a music score (like WolframTones)
Ok, so using some basic principles of Cellular Automata, I've managed to get a program running which generates a set of data calculated from rules. 好的,因此,使用“细胞自动机”的一些基本原理,我设法使一个程序运行,该程序生成根据规则计算出的一组数据。 Each cell is a boolean.
每个单元格都是一个布尔值。
Currently I am storing it as so - boolean[][] data - where the first index is the row and the second is the cell. 目前,我将其存储为boolean [] []数据-第一个索引是行,第二个索引是单元格。
Now I have gotten up to the point where I would like to convert that music into a score (stored as an array). 现在,我想把音乐转换成乐谱(存储为数组)。 On the page it shows a diagram of how it would be converted from CA data -
在页面上 ,该图显示了如何从CA数据进行转换的图表-
to score data 评分数据
I have trouble understanding how this would be done progmatically using my storage scheme. 我很难理解如何使用我的存储方案进行编程。 If anyone could help that would be great, I can provide more info if necessary.
如果有人可以帮助您,那将非常有用,如有必要,我可以提供更多信息。
The mapping looks straight forward: 映射看起来很直接:
target[x, y] = source[OFFSET - y, x]
where OFFSET
is the index of the last row to copy ( 33
if I counted right). 其中
OFFSET
是要复制的最后一行的索引(如果我计算正确,则为33
)。
Your implementation could just use two nested loops to copy the array. 您的实现可以只使用两个嵌套循环来复制数组。
EDIT: 编辑:
This is what your converter could look like: 这是您的转换器的外观:
public class Converter
{
public static boolean[][] convert(boolean[][] source, int offset, int width)
{
final boolean[][] target = new boolean[width][source.length];
for(int targetRow=0 ; targetRow<width ; targetRow++)
{
for(int targetCol=0 ; targetCol<source.length ; targetCol++)
{
target[targetRow][targetCol] = source[targetCol][offset + width-1 - targetRow];
}
}
return target;
}
}
This is the output of the test-code below (original array and the transformed array) using an offset of 2
(the first two lines are omitted) and a width of 7
(seven columns are transformed): 这是下面的测试代码(原始数组和转换后的数组)的输出,使用偏移量
2
(省略了前两行)和宽度7
(转换了七列):
█
███
██ █
██ ████
██ █ █
██ ████ ███
█ █
██
█ █ █
██ ███
██ █
██ █
██
The test-code is to convert the String-definition of the source-array and to output the array-content: 测试代码是要转换源数组的字符串定义并输出数组内容:
public class ConverterTest
{
private final static int OFFSET = 2;
private final static int WIDTH = 7;
private static final String[] sourceString = {
" █ ",
" ███ ",
" ██ █ ",
" ██ ████ ",
" ██ █ █ ",
"██ ████ ███",
};
public static void main(String[] args)
{
final boolean[][] source = getSourceArray();
printArray(source);
final boolean[][] target = Converter.convert(source, OFFSET, WIDTH);
printArray(target);
}
private static boolean[][] getSourceArray()
{
final boolean[][] sourceArray = new boolean[sourceString.length][sourceString[0].length()];
for(int row=0 ; row<sourceString.length ; row++)
{
for(int col=0 ; col<sourceString[0].length() ; col++)
{
sourceArray[row][col] = (sourceString[row].charAt(col) != ' ');
}
}
return sourceArray;
}
private static void printArray(boolean[][] arr)
{
for(int row=0 ; row<arr.length ; row++)
{
for(int col=0 ; col<arr[0].length ; col++)
{
System.out.print(arr[row][col] ? '█' : ' ');
}
System.out.println();
}
System.out.println();
}
}
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