生成UV球的搅拌器性能问题

Question

When I run this script:

import bpy, time
t0 = time.time()

for i in range(1000):
    bpy.ops.mesh.primitive_uv_sphere_add()

    if i % 100 == 0:
        print(time.time()-t0)
        t0 = time.time()

This is the output (exponential growth vs. time):

1.1920928955078125e-05
0.44658803939819336
0.46373510360717773
0.5661759376525879
0.7258329391479492
0.9994637966156006
1.381392002105713
1.8257861137390137
2.4634311199188232
3.2817111015319824

Why does this happen? Is there a better approach?

I am running this on a server with ample memory, and I know Blender can expand to use most of it (it does in rendering).

Answer 1

The quick answer:

bpy.ops.object.select_all(action='DESELECT')
bpy.ops.mesh.primitive_uv_sphere_add()
sphere = bpy.context.object

for i in range(1000):
    ob = sphere.copy()
    ob.data = sphere.data.copy()
    bpy.context.scene.objects.link(ob)
bpy.context.scene.update()

Explanation:

Anything in bpy.ops.* causes a scene redraw with each call. You want to avoid calling these in loops. The above script calls lower-level copy() methods, which don't redraw. If you want linked duplicates, you can remove the sphere.data.copy() line.

This solution is not my own. Kudos go to CoDEmanX over at BlenderArtists for this answer!