从另一个Shell脚本仅调用一个函数

Question

cat global_features_script.sh

.child1_script.sh
.child2_script.sh

    function svn_credentials
    {
        echo -n "Enter the svn username and press [ENTER]: " > /dev/tty
        read svn_username
        echo -n "Enter the svn commit message and press [ENTER]: "  > /dev/tty
        read svn_message
        echo -n "Enter your svn password and press [ENTER]: "  > /dev/tty
        read -s svn_password
    }
    if [ a == b]
    then
    echo "a is equal to be b"
    else
    echo "a is not equal to b"
    fi

    function exit_error
    {
    echo " There is an error in the command, please check it"
    exit 1
    }

cat child_script.sh

. global_features_script.sh
svn_wc=temp_dir
svn_credentials # calling function from global_features_script.sh
svn commit $svn_wc -m "$svn_message" --username $svn_username --password $svn_password

When i execute: . child_script.sh

expected output: I need to get run only one function (svn_credentails) from global_features_script.sh

output i am getting is: its calling all other functions and also other shell scripts that are listed in global_features_script.sh

Answer 1

From my understanding, the . master_script.sh . master_script.sh will just insert the master script into the execution of the child_script.sh , so you'll actually be running both scripts. The simplest thing, in my opinion, would be to just create a common_functions.sh header file that has all the common functions in it, and then just source that header file in either master or child.

A quick syntax note, i'd recommend using source master_script.sh rather than the . . It should be functionally the same, but it's slightly cleaner and more readable.