![](/img/trans.png)
[英]Call one shell script from another script and store that output of that script in a variable
[英]call only one function from another shell script
猫global_features_script.sh
.child1_script.sh
.child2_script.sh
function svn_credentials
{
echo -n "Enter the svn username and press [ENTER]: " > /dev/tty
read svn_username
echo -n "Enter the svn commit message and press [ENTER]: " > /dev/tty
read svn_message
echo -n "Enter your svn password and press [ENTER]: " > /dev/tty
read -s svn_password
}
if [ a == b]
then
echo "a is equal to be b"
else
echo "a is not equal to b"
fi
function exit_error
{
echo " There is an error in the command, please check it"
exit 1
}
猫child_script.sh
. global_features_script.sh
svn_wc=temp_dir
svn_credentials # calling function from global_features_script.sh
svn commit $svn_wc -m "$svn_message" --username $svn_username --password $svn_password
当我执行时: child_script.sh
预期的输出:我只需要从global_features_script.sh运行一个函数(svn_credentails)
我得到的输出是:它调用所有其他函数以及global_features_script.sh中列出的其他shell脚本
据我了解, . master_script.sh
. master_script.sh
只会将主脚本插入到child_script.sh
的执行中,因此您实际上将在运行这两个脚本。 在我看来,最简单的事情是创建一个具有所有常用功能的common_functions.sh
头文件,然后仅在master或child头中提供该头文件。
快速的语法注释,我建议使用source master_script.sh
而不是.
。 它在功能上应该是相同的,但是它稍微更整洁并且更具可读性。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.