[英]Formula for number of rows from a x4 grid
Ok so I am currently setting up a grid, each row will have 4 objects. 好的,所以我当前正在设置一个网格,每行将有4个对象。 The number of rows must be calculated according to this constraint.
行数必须根据此约束进行计算。
So if I had 15 objects, I need 4 rows. 因此,如果我有15个对象,则需要4行。 If i had 12 objects I need 3 rows.
如果我有12个对象,我需要3行。
Somehow I need some sort of mathematical formula that will perform and return this number. 我不知何故需要某种数学公式来执行并返回该数字。 So when I say to the function I have x number of objects, it will return the number of rows.
因此,当我对函数说我有x个对象时,它将返回行数。
Thanks for any help. 谢谢你的帮助。
ceil(x / 4.0)
You want the ceiling, not the floor of the resultant value. 您需要上限,而不是结果值的下限。 Otherwise, you won't be able to fit say 15 into 4 rows.
否则,您将无法将15放入4行。
Warning: readability swamp 警告:可读性沼泽
floor((obj - 1) / 4) + 1
楼板((obj-1)/ 4)+ 1
where obj is the number of objects in your question. 其中obj是您问题中的对象数。
or even more concise: 甚至更简洁:
floor((obj + 3) / 4)
地板((obj + 3)/ 4)
One liner! 一班!
Floor usually comes with the language's integer division operator (eg, Java, C++), so it's probably shorter to implement. Floor通常带有语言的整数除法运算符(例如Java,C ++),因此实现起来可能要短一些。
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