在awk中使用记录分隔符

Question

I have

$ cat awktestf 
a++
b++
c++

I am doing and I get

cat  awktestf | awk 'BEGIN { RS="++" ; OFS="@"; ORS="()" } { print $0 } END {print "I am done" }'
a()
b()
c()
()I am done()abc@abc:~$ 

My question is why am I getting an extra () at the end?

Even this does not work:

$ echo 'a++
> b++
> c++' | awk 'BEGIN { RS="++" ; OFS="@"; ORS="()" } { print $0 } END {print "I am done" }'
a()
b()
c()
()I am done()abc@abc:~$ 

Answer 1

ORS is appended to the end of each output record. Hence your "I am done" ends with () .

---

Misunderstood the question the first time.

This

a++
b++
c++

translates to

a++\nb++\nc++\n

After splitting into records using RS , you get these records

1. a
2. \\nb
3. \\nc
4. \\n

When you print them, each record is terminated with ORS , () , so

a()\nb()\nc()\n()

You added "I am done"

a()\nb()\nc()\n()I am done()

Hence this is displayed as

a()
b()
c()
()I am done()

(Since the last line does not end with a newline, your prompt shows on the same line)

Answer 2

Probably you have a blank line at the end of the your file.

Since OFS is set to () , it gets printed after every line that's printed to the output. Just remove the blank line from your input file.

Side note: you don't have to cat the file then pipe to awk. Simply use awk :

awk ' .... ' file