如何在for循环中使用min（x，y）计算最小值？ 取决于用户输入

Question

So I have been trying to tackle this problem for a while. Many things I have attempted have failed. Is there a way to add to what I already have?

for(int ii = 1, j = 0; j <= copySel ; ii++, j++) {    
             int check;
             int x, y;
                // Prompt as follows
                System.out.print("Enter value " + ii + ": ");
                try {
                    c = Get();
                }
                catch (InputMismatchException e) {
                    input
                    System.out.println("Invalid input!");
                    ii--;
                }check = c;   
                 x = check; // I want to try to copy this 
                 y = check - 1; // and copy this
                min(x , y) // trying to acheive this




                System.out.println(check + " " + x + " " + y);

        }

Sorry about the formatting. It is my screen.

Basically let us say user puts in 25 for first input. I want x = 25.
Then user inputs -11.                                 I want y = -11.
Compare minimum                                       z = -11.
then                                                  x = z = -11;
User input 33.                                        y = 33
annd so on..

So i ended up with something like

for(int ii = 1, j = 0; j <= copySel ; ii++, j++) {    
             int check;
             int x = 0, y = 0, z;
                // Prompt as follows
                System.out.print("Enter value " + ii + ": ");
                try {
                    c = Get();
                }
                catch (InputMismatchException e) {

                    System.out.println("Invalid input!");
                    ii--;
                }check = c;
               x = check;
               z = x;   
            if (j % 2 == 1)
            {
                y = check;
                Math.min(z, y);
            }


                System.out.println(check + " " + x + " " + y + " " + z);

        }

Answer 1

I guess you are trying to get the minimum value from the current input and last minimum value. Definitely it will be the minimum of all the numbers provided. Then all you need is to save minimum value from the last turn and compare it with input in the next one.

for(int ii = 1, j = 0; j <= copySel ; ii++, j++) {  //btw, what is 'j' for? attempt count?
         boolean mode; //true = minimum, false = maximum
         boolean firstNumber = true;
         int check; //user input
         int lastValue; //will be the storage
            // Prompt as follows
            System.out.print("Enter value " + ii + ": ");
            try {
                c = Get();
            }
            catch (InputMismatchException e) {
                input
                System.out.println("Invalid input!");
                ii--;
            }
             check = c;
             if (firstNumber) { //first input has nothing to compare with
                 lastValue = check;
                 firstNumber = false;
                 continue;
             }
             lastValue = mode ? min(check, lastValue) : max(check, lastValue);
             /* you should also implement max() method if you want to be able to find maximum
             *  if you don't, just write lastValue = min(check, lastValue);
             *  and remove other 'mode' dependancies.
             */


             System.out.println((mode ? "minimum is: " : "maximum is: ") + String.valueOf(lastValue));

    }

hope I have understood your problem correct.